leap = False
import datetime
year = int(input(“Enter a year: “))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(“{0} is a leap year”.format(year))
else:
print(“{0} is not a leap year”.format(year))
else:
print(“{0} is a leap year”.format(year))
else:
print(“{0} is not a leap year”.format(year))
import time
import datetime
def is_leap(year):
leap = False
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
leap = True
else:
leap = False
else:
leap = True
return leap
print(“welcome to the year 2000”)
def is_leap(year):
return year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)
year = int(input())
print(is_leap(year))
The leap year program in python is the program which checks whether a given year is the leap year or not.
In this program, we ask the user to input a year and then we use if…else statement to check whether it is a leap year or not. The condition for a leap year is as follows :
The condition for a leap year is as follows :
If the year is divisible by 4 then it is a leap year but if the year is century year like 2000, 1900, 2100 then it must be divisible by 400.
Tomy is a contributor at AskMeCode. We are committed to providing well-researched, accurate, and valuable content to our readers.
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